Àwọn Ìṣàmúlò-ètò

Calculate sample or population standard deviation, variance and mean.

Àwọn ìṣàmúlò-ètò —

Àwọn ìṣàfarawé —

Àwọn ìṣàmúlò-ètò —

Àwọn ìṣàmúlò-ètò àwọn ìṣàmúlò-ètò àwọn àwọn ìṣàmúlò-ètò —

Kéré —

Òkè —

Àwọn Ìjánu-ìsún —

Àwọn Ìtàn —

Àwọn Àtòjọ-ẹ̀yàn àwọn ìṣàmúlò-ètò

Ńlà àwọn àwọn ààtò àtòjọ-ẹ̀yàn yìí?

Àkóónú ìṣàmúlò-ètò yìí

Standard deviation measures how spread out a data set is around its mean: a small value means the numbers cluster tightly near the average, a large one means they are widely scattered. This calculator computes both the sample standard deviation (dividing the sum of squared deviations by n − 1, Bessel’s correction) and the population standard deviation (dividing by n), and reports the variance, mean, range and the sum of squared deviations it used. Choose sample when your numbers are a subset drawn from a larger group, and population when they are the entire group.

The method has four steps: find the mean, subtract it from each value to get the deviations, square those deviations and add them up, then divide by n − 1 (sample) or n (population) and take the square root. The square root returns the answer to the same units as the original data, which is why standard deviation is usually preferred over variance for interpretation.

Worked example: for 2, 4, 4, 4, 5, 5, 7, 9 the mean is 5. The squared deviations sum to 32, so the population variance is 32 ÷ 8 = 4 and the population standard deviation is √4 = 2; the sample version divides 32 by 7, giving about 4.57 and a standard deviation of roughly 2.14. The deviation table below shows each value’s distance from the mean and its squared deviation so you can follow the calculation.

Àwọn Àtòjọ-ẹ̀yàn

Kini iyatọ laarin ayẹwo ati iyatọ asiko ti ajọṣepọ?

Foomúládùóruń tí a lò ǹ jẹ́ pé a lè pọ̀lú àwọn iyatọ́ kejì tí a tí wa ní n; foomúládùóruń tí a lò ní n − 1. N − 1 (àwọn àtílẹ̀ Bessel) jẹ́ pé a lè pọ̀lú àwọn iyatọ́ tí a tí wa ní inú awoṣe.

Kini idi ti a fi fi àwọn ìṣàfarawé àwọn ìṣàfarawé?

Squaring makes every deviation positive so they do not cancel out, and it weights larger deviations more heavily. Taking the square root at the end returns the measure to the original units of the data.

Bawo ni mo ṣe lè ṣé ìṣàfarawé ìṣàfarawé ìpéwọ̀n nípa ìṣẹ̀dá?

Find the mean, subtract it from each value to get the deviations, square each deviation and add them up, then divide by n − 1 for a sample or n for a population and take the square root of that result.

Kini ìṣàfarawé ìpèwọ̀n tí o dara?

Kò ní fálù "ìbára" ní gbogbo agbaye — o dá lórí ìjáde náà àti àgbègbè data rẹ. Ìdàràn-ìgbà ní a lè fi hàn nínú àwọn àwọn ààyè; àwọn ààyè tí a fi pamọ́ fún àwọn àwọn owó ilè lè jẹ́ nla fún àwọn

Àwọn ìṣàfarawé àwọn ìṣàfarawé ìṣàfarawé lè jẹ́ ìwọ̀n tàbí ìṣàfarawé ìṣàfarawé?

O lè jẹ́ sáà, tí o bá ṣẹlẹ̀ látigbá tí àwọn fálù gbogbo náà bá jẹ́ ìdáràn nípa àwọn àwọn ìṣàfarawé. O kò lè jẹ́ aládàrà, nitori o jẹ́ áríǹ kọ̀ǹpútà tí a bá sọ̀rọ̀ àwọn

Kini idi tí ìṣàmúlò-ètò ìṣàmúlò-ètò náà fi fẹ́ àwọn fálù mejì ní àwọn ìṣàmúlò-ètò náà?

The sample formula divides by n − 1, so a single value would divide by zero and is left undefined. A sample standard deviation only makes sense once you have two or more observations to compare.

API — ló àwọn ìṣàmúlò-ètò yìí láti inú ìṣàmúlò-ètò

Fi àwọn ìṣàmúlò-ètò yìí kọ̀ǹpútà yìí láti jẹ́ ààyè-iṣẹ́ JSON tí a tí fi pamọ́ - kò ní bọ́tìnì kan tí a fẹ́. Fi àwọn fálù ààyè-iṣẹ́ sílẹ̀ sí bí àwọn àwọn ìṣàmúlò-ètò àti JSON. Anything you omit uses the same default this page is pre-filled with; an unknown parameter is a 400, never a silent zero. Ka àwọn àkọlé API kíkún →

Àwọn Ààyè Ìjánu-ìṣàmúlò-ètò

GET https://calculator.free/api/v1/standard-deviation/

curl

curl "https://calculator.free/api/v1/standard-deviation/?numbers=9, 2, 5, 4, 12, 7, 8, 11, 9, 3, 7, 4, 12, 5, 4, 10, 9, 6, 9, 4&type=sample"

JavaScript `fetch()`

const r = await fetch(
  "https://calculator.free/api/v1/standard-deviation/?" + new URLSearchParams({
    "numbers": "9, 2, 5, 4, 12, 7, 8, 11, 9, 3, 7, 4, 12, 5, 4, 10, 9, 6, 9, 4",
    "type": "sample"
  }));
const data = await r.json();
console.log(data.results);

Results are estimates for general guidance only, not financial, medical or tax advice.

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