Ҳисобкунии қонуни гази идеалӣ
Solve PV = nRT for any variable, in your choice of pressure, volume and temperature units.
Натиҷаҳо ҳангоми навиштан нав карда мешаванд.
Дар бораи ин ҳисобкунак
The ideal gas law ties together the four state variables of a gas in one equation, PV = nRT: pressure times volume equals the number of moles times the gas constant times the absolute temperature. The constant R = 8.314462618 J/(mol·K) in SI units. Rearranged, you can solve for any variable — P = nRT/V, V = nRT/P, n = PV/RT or T = PV/nR — and this calculator does exactly that, converting pressure (Pa, kPa, bar, atm, mmHg, psi), volume (m³, L, mL, cm³) and temperature (K, °C, °F) internally so you can work in whatever units you have.
The classic worked example is one mole of gas at standard temperature and pressure: at 0 °C (273.15 K) and 1 atm, V = nRT/P = 1 × 8.314 × 273.15 / 101,325 ≈ 0.0224 m³, or the familiar 22.4 litres per mole. Heat that gas to 300 K at constant pressure and the volume rises in proportion, since V ∝ T. A crucial detail: temperature must be absolute — always convert °C or °F to kelvin (add 273.15 to °C) before the math, which the calculator handles for you.
The law is called "ideal" because it assumes gas molecules have no volume and do not attract one another. Real gases follow it closely at ordinary pressures and temperatures well above their boiling point, and it is the everyday tool for scuba and diving gas calculations, chemistry stoichiometry of gases, HVAC and pneumatics, and estimating how a balloon or tyre responds to heating and cooling. It becomes less accurate at very high pressure or near condensation, where equations like van der Waals do better.
Саволҳои маъмул
Қонуни гази идеалӣ чист?
PV = nRT links pressure, volume, moles and temperature of an ideal gas through the constant R = 8.314 J/(mol·K). Rearrange it to solve for any single variable.
Якиятҳои дуруст кадомҳоянд?
Internally everything is SI — pascals, cubic metres, moles and kelvin — with R = 8.314. One mole of gas at 0 °C (273.15 K) and 1 atm occupies about 22.4 L (0.0224 m³). Enter any units you like; the calculator converts for you.
Чаро ҳарорат дар Келвин бошад?
PV = nRT ҳарорати мутлақро истифода мебарад, ки дар он 0 K сифр аст. Целсий ва Фаренгейт ҳар ду сифрҳои ихтиёрӣ доранд, бинобар ин ворид кардани °C ба таври мустақим ҷавоби хато медиҳад. Ба °C 273. 15 илова кунед, то ки Келвинро гиред - ҳисобкунак инро худкорона иҷро мекунад.
Дар ин ҷо барои дарёфти иқтидори атомӣ ва молекулавӣ чӣ кор кардан лозим аст?
Standard temperature and pressure is commonly 0 °C and 1 atm, at which one mole of an ideal gas occupies about 22.4 litres. This "molar volume" is a handy check: if your result for one mole near those conditions is far from 22.4 L, recheck the units.
Қонунҳои гази идеалӣ кай вайрон мешаванд?
It is very accurate at moderate pressures and temperatures well above the boiling point, but grows inaccurate at high pressure or near condensation, where molecular volume and attractions matter. Real-gas equations like van der Waals handle those.
Тағйир додани як тағирёбанда ба дигарон чӣ гуна таъсир мерасонад?
At fixed moles, pressure and volume are inversely related (Boyle’s law), while volume and absolute temperature are directly related (Charles’s law). Heat a sealed rigid container and the pressure rises in proportion to the kelvin temperature.
Кадом арзиши R- ро истифода барам?
It depends on units. In SI it is 8.314 J/(mol·K); in litre-atmospheres it is 0.08206 L·atm/(mol·K). This calculator works in SI internally with R = 8.314, so you can enter any units and it reconciles them.
API — истифодаи ин ҳисобкунак аз рамз
Ин ҳисобгарро ҳамчун нуқтаи охирини JSON озод даъват кунед - ягон калид лозим нест. Қимматҳои заминаро дар поён ҳамчун параметрҳои пурсиш ё JSON фиристед. Ҳар чизе, ки шумо нобуд мекунед, ҳамон пешфарзи ин саҳифаро истифода мебарад, ки пешакӣ пур карда шудааст; параметри номуайян 400 аст, ҳеҷ гоҳ сифр нест. Хондани ҳуҷҷати пурраи API →
Нуқтаи охирин
GET https://calculator.free/api/v1/ideal-gas-law/curl
curl "https://calculator.free/api/v1/ideal-gas-law/?solve=volume&pressure=1&pressure_unit=atm&volume=22.4&volume_unit=l&moles=1&temperature=273.15&temperature_unit=k"JavaScript fetch()
const r = await fetch(
"https://calculator.free/api/v1/ideal-gas-law/?" + new URLSearchParams({
"solve": "volume",
"pressure": "1",
"pressure_unit": "atm",
"volume": "22.4",
"volume_unit": "l",
"moles": "1",
"temperature": "273.15",
"temperature_unit": "k"
}));
const data = await r.json();
console.log(data.results);Ин натиҷаҳо танҳо барои маслиҳати умумӣ, на маслиҳати молиявӣ, тибби ё андозӣ мебошанд.