Ka taea te tātaitai te ture o te korohū tino pai
Whakarautaki PV = nRT mō ētahi tāupe, i roto i tō tātou kōwhiringa o ngā wae o te pēhanga, te rōrahi me te pāmahana.
Ka whakahōutia ngā hua i te wā e tātuhi ana.
Mo tēnei tātaitai
the ideal gas law, the volume of a gas is equal to the volume of the gas itself, and the volume of the gas is equal to the volume of the gas itself. The ideal gas law is a mathematical equation that describes the volume of a gas, and the volume of a gas is equal to the volume of the gas itself. The ideal gas law is a mathematical equation that describes the volume of a gas, and the volume of the gas itself. The ideal gas law is a mathematical equation that describes the volume of a gas, and the volume of the
Ko nga pātai e pā ana
He aha te ture o te korohū tino pai?
E hono ana a PV = nRT ki te pēhanga, te rōrahi, ngā momo me te pāmahana o te korohū tino pai mā te taupānga R = 8.314 J/(mol·K). Ka whakahōutia kia whakaotitia ai tētahi tāupe kotahi.
He aha nga wae tika?
Internally everything is SI — pascals, cubic metres, moles and kelvin — with R = 8.314. One mole of gas at 0 °C (273.15 K) and 1 atm occupies about 22.4 L (0.0224 m³). Enter any units you like; the calculator converts for you.
He aha te mahana me te tauwāhi i roto i te Kelvin?
PV = nRT ka whakamahia te pāmahana tino pai, i reira ko te 0 K te kore tino pai. He kore āhua noa te Celsius me te Fahrenheit, nā reira ko te whakapāpātanga ki te °C e tuku ana i ngā whakautu hē. Tāpiri i te 273.15 ki te °C hei whiwhi i te Kelvin — ka mahi ngāwari tēnei e te tātaitai.
He aha te STP me te rōrahi molar?
Ko te tikanga he 0 °C te pāmahana me te pēhanga paerewa me te 1 atm, i reira kotahi te momo korohū tino pai e noho ana tata ki te 22.4 lita. He tino tika tēnei "tōpū molar": mēnā kei te tawhiti o tōtou hua mō tētahi molaro tata ki ēnei āhuatanga mai i te 22.4 L, ka arotake anō ngā wae.
He pēhea te whakapeka o te ture korohū tino pai?
He tino tika ki ngā pēhanga pūnoa me ngā mahana i runga ake i te pito o te whakato, engari kāore e tika ana i ngā pēhanga tiketike, i te tata rānei ki te whakatōpūtanga, i te wāhi e hira ana te rahi rāpoi ngota me te āhua o te āhua o te rāpoi ngota.
He pēhea te pānga o te huringa o tētahi tāupe ki ētahi atu?
I ngā mārō pūmau, he pānga pāhono te pēhanga me te rōrahi (te ture a Boyle), ā, he pāhono hāngai te rōrahi me te pāmahana tino pai (te ture a Charles).
He aha te uara o R me whakamahia e au?
E whakawhirinaki ana ki ngā wae. I roto i te SI he 8.314 J / (mol · K); i roto i ngā haurangi-wae he 0.08206 L · atm / (mol · K). Ka mahi tēnei tātaitai i roto i te SI i roto me R = 8.314, nō reira ka taea e koe te tāuru i ētahi wae, ā, ka whakahōu i a rātou.
API — whakamahi tēnei tātaitai mai i te waehere
E kī ana tēnei tātaitai hei wāhi mutunga kore JSON - kāore he kī e hiahiatia ana. Ka tukuna ngā uara āpure i raro nei hei tohutoro pātai, JSON rānei. Ka pānui te papatono API katoa →
Whakamutunga
GET https://calculator.free/api/v1/ideal-gas-law/curl
curl "https://calculator.free/api/v1/ideal-gas-law/?solve=volume&pressure=1&pressure_unit=atm&volume=22.4&volume_unit=l&moles=1&temperature=273.15&temperature_unit=k"JavaScript fetch()
const r = await fetch(
"https://calculator.free/api/v1/ideal-gas-law/?" + new URLSearchParams({
"solve": "volume",
"pressure": "1",
"pressure_unit": "atm",
"volume": "22.4",
"volume_unit": "l",
"moles": "1",
"temperature": "273.15",
"temperature_unit": "k"
}));
const data = await r.json();
console.log(data.results);Ko ngā hua he whakataunga mō te tohutohu ahuwhānui anake, ehara i te tohutohu moni, rongoā, tāke rānei.