Kalkulatur tal-Ħlas tal-Kondensatur
Iċċartja l-kurva taċ-ċarġ jew tal-ħruġ ta' ċirkwit RC bil-kostant tal-ħin u l-enerġija.
Riżultati aġġornament kif inti tip.
Dwar din il-kalkulatur
Capacitor charge is the electric charge a capacitor holds in the field between its plates, Q = C × V in coulombs, and the energy stored is E = ½ × C × V² in joules, so doubling the voltage quadruples the stored energy. When you charge a capacitor through a series resistor, the voltage does not jump instantly — it rises along the curve V(t) = V × (1 − e^(−t/τ)); discharging, it falls along V(t) = V × e^(−t/τ). Both are governed by the time constant τ = R × C, the natural timescale of the RC circuit.
After one time constant the capacitor reaches about 63% of the supply voltage when charging (or falls to 37% when discharging); after 5τ it is within 1% of its final value and is treated as fully charged or discharged. For example, a 1,000 µF capacitor charged through a 1 kΩ resistor has τ = 1,000 × 10⁻⁶ × 1,000 = 1 second, so it is 63% charged after 1 s and essentially full after 5 s. At 5 V that same capacitor stores Q = 0.001 × 5 = 0.005 C and E = ½ × 0.001 × 25 = 0.0125 J.
Enter the supply voltage, capacitance and series resistance and the calculator returns the full charge, the stored energy, the time constant, the settling time (5τ), the voltage at a chosen instant, and the whole charge or discharge curve. These numbers are the everyday basis for RC timing circuits, power-supply smoothing, debounce delays, flash-photography energy storage and the turn-on delays in analogue electronics.
Mistoqsijiet li jsiru ta' spiss
X'inhu l-ħin kostanti ta'ċirkwit RC?
Il-kostant tal-ħin τ = R × C huwa l-ħin biex jiċċarġja għal madwar 63% tal-vultaġġ tal-provvista. Wara 5τ il-capacitor huwa meqjus bħala ċċarġjat kompletament (> 99%).
Kemm enerġija ma capacitor ħżin?
L-enerġija hija E = ½ × C × V². Kapaċitur ta' 1000 µF f'5 V jaħżen ½ × 0.001 × 25 = 0.0125 joules.
X'inhi d-differenza bejn l-iċċarġjar u l-ħatt?
L-iċċarġjar jiżdied lejn il-provvista bħala V(1 − e^(−t/τ)); l-iskarika tonqos mill-vultaġġ tal-bidu bħala V·e^(−t/τ) It-tnejn jilħqu ~99% tal-bidla wara 5 kostanti tal-ħin.
Kemm ħlas ma capacitor żomm?
Il-piż huwa Q = C × V f'coulombs. A 1,000 µF capacitor f'5 V iżomm 0.001 × 5 = 0.005 C. Kapaċitanza akbar jew vultaġġ ogħla t-tnejn jaħżnu aktar piż, fi proporzjon dirett.
Kemm idum sakemm il-kapaċitatur ikun iċċarġjat kompletament?
Prattikament, wara ħames kostanti ta' żmien (5τ = 5RC) huwa fi ħdan madwar 1% tal-provvista u ttrattat bħala sħiħ.B'1 kΩ resistor u 1,000 µF capacitor τ huwa 1 s, hekk huwa essenzjalment iċċarġjat wara bejn wieħed u ieħor 5 sekondi.
Liema perċentwal jintlaħaq wara kull kostanti ħin?
L-iċċarġjar jilħaq madwar 63% wara 1τ, 86% wara 2τ, 95% wara 3τ, 98% wara 4τ u 99% wara 5τ. L-iskarika ssegwi l-immaġni tal-mera: 37%, 14%, 5%, 2% u 1% jibqgħu fl-istess punti.
Għaliex iżżid resistor tas-serje fil-livelli kollha?
Mingħajr dan, il-pick kurrenti fil-swiċċ fuq huwa limitat biss minn reżistenza stray u jistgħu jkunu enormi; ir-reżistenza jagħmel il-ħin prevedibbli, li huwa eżattament dak RC timers, filtri u ċirkuwiti debounce jiddependu fuq.
API — uża din il-kalkulatur mill-kodiċi
Sejjaħ dan il-kalkulatur bħala punt aħħari JSON b'xejn — l-ebda ċavetta meħtieġa Ibgħat il-valuri tal-qasam hawn taħt bħala parametri tal-mistoqsija jew JSON. Kull ħaġa li tħalli barra tuża l-istess default li din il-paġna hija mimlija minn qabel; parametru mhux magħruf huwa 400, qatt żero sieket. Aqra d-dokumenti sħaħ tal-API →
Punt aħħari
GET https://calculator.free/api/v1/capacitor-charge/curl
curl "https://calculator.free/api/v1/capacitor-charge/?mode=charge&voltage=5&capacitance=1000&resistance=1000"JavaScript fetch()
const r = await fetch(
"https://calculator.free/api/v1/capacitor-charge/?" + new URLSearchParams({
"mode": "charge",
"voltage": "5",
"capacitance": "1000",
"resistance": "1000"
}));
const data = await r.json();
console.log(data.results);Ir-riżultati huma stimi għal gwida ġenerali biss, mhux parir finanzjarju, mediku jew tat-taxxa.