Capacitor Charge Calculator
या यंत्रात यंत्राच्या गतीचा आणि यंत्राच्या गतीचा व यंत्राच्या गतीचा गुणोत्तराचा एकमेकांशी संबंध असतो.
तुम्ही टाइप करतेवेळी परिणाम अद्ययावत केले जातात.
या कॅल्क्युलेटरविषयी
Capacitor charge is the electric charge a capacitor holds in the field between its plates, Q = C × V in coulombs, and the energy stored is E = ½ × C × V² in joules, so doubling the voltage quadruples the stored energy. When you charge a capacitor through a series resistor, the voltage does not jump instantly — it rises along the curve V(t) = V × (1 − e^(−t/τ)); discharging, it falls along V(t) = V × e^(−t/τ). Both are governed by the time constant τ = R × C, the natural timescale of the RC circuit.
After one time constant the capacitor reaches about 63% of the supply voltage when charging (or falls to 37% when discharging); after 5τ it is within 1% of its final value and is treated as fully charged or discharged. For example, a 1,000 µF capacitor charged through a 1 kΩ resistor has τ = 1,000 × 10⁻⁶ × 1,000 = 1 second, so it is 63% charged after 1 s and essentially full after 5 s. At 5 V that same capacitor stores Q = 0.001 × 5 = 0.005 C and E = ½ × 0.001 × 25 = 0.0125 J.
Enter the supply voltage, capacitance and series resistance and the calculator returns the full charge, the stored energy, the time constant, the settling time (5τ), the voltage at a chosen instant, and the whole charge or discharge curve. These numbers are the everyday basis for RC timing circuits, power-supply smoothing, debounce delays, flash-photography energy storage and the turn-on delays in analogue electronics.
वारंवार विचारले जाणारे प्रश्न
रॉकेटच्या गतीचा वेग किती आहे?
The time constant τ = R × C is the time to charge to about 63% of the supply voltage. After 5τ the capacitor is regarded as fully charged (>99%).
याचा वापर करून किती ऊर्जा मिळवता येते?
Energy is E = ½ × C × V². A 1000 µF capacitor at 5 V stores ½ × 0.001 × 25 = 0.0125 joules.
याचा अर्थ काय आणि त्याचे परिणाम काय?
Charging rises toward the supply as V(1 − e^(−t/τ)); discharging falls from the starting voltage as V·e^(−t/τ). Both reach ~99% of the change after 5 time constants.
एका वेळी किती वजनाची वस्तू टाकली जाते?
The charge is Q = C × V in coulombs. A 1,000 µF capacitor at 5 V holds 0.001 × 5 = 0.005 C. Larger capacitance or higher voltage both store more charge, in direct proportion.
याची प्रत किती दिवस टिकते?
Practically, after five time constants (5τ = 5RC) it is within about 1% of the supply and treated as full. With a 1 kΩ resistor and 1,000 µF capacitor τ is 1 s, so it is essentially charged after roughly 5 seconds.
प्रत्येक वेळी किती टक्के वेळ स्थिर आहे?
Charging reaches about 63% after 1τ, 86% after 2τ, 95% after 3τ, 98% after 4τ and 99% after 5τ. Discharging follows the mirror image: 37%, 14%, 5%, 2% and 1% remaining at the same points.
या सर्व गोष्टींमुळेच एक प्रकारचा राग निर्माण होतो.
रोधक चार्जिंग वेग निश्चित करतो. याशिवाय, चालू- चालू वेळी विद्युत स्पीकर्स फक्त भटक्या रोधकाद्वारे मर्यादित असतात व मोठे असू शकतात; रोधक वेळ निश्चित करतो, जे RC टाइमर, फिल्टर व डेबॉनस परिपथावर अवलंबून असते.
API — कोड पासून हे कॅल्क्युलेटर वापरा
या कॅल्क्युलेटरला मोफत JSON अंतबिंदू म्हणून कॉल करा - कुठलीही कि आवश्यक नाही. खालील क्षेत्र मूल्ये क्वेरी पेरेन्ट किंवा JSON म्हणून पाठवा. तुम्ही गळविलेले सर्व काही हे पान पूर्वदाखल करीता वापरले जाते; अपरिचीत बाब 400 आहे, कधीही मंद शून्य नाही. पूर्ण API दस्तऐवजीकरण वाचा →
अंतबिंदू
GET https://calculator.free/api/v1/capacitor-charge/curl
curl "https://calculator.free/api/v1/capacitor-charge/?mode=charge&voltage=5&capacitance=1000&resistance=1000"JavaScript fetch()
const r = await fetch(
"https://calculator.free/api/v1/capacitor-charge/?" + new URLSearchParams({
"mode": "charge",
"voltage": "5",
"capacitance": "1000",
"resistance": "1000"
}));
const data = await r.json();
console.log(data.results);याचे परिणाम केवळ सामान्य मार्गदर्शनासाठी आहेत, आर्थिक, वैद्यकीय किंवा कर सल्लागार नाही.