电容电量计算器

显示具有时常和能量的RC电路充电或排气曲线。

V
µF
Ω
s
全额费用 (C) —
存储能源(J) —
Time constant τ (s) —
时压伏(V) —
确定时间 5-(s) —

输入结果时更新 。

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关于此计算器

Capacitor charge is the electric charge a capacitor holds in the field between its plates, Q = C × V in coulombs, and the energy stored is E = ½ × C × V² in joules, so doubling the voltage quadruples the stored energy. When you charge a capacitor through a series resistor, the voltage does not jump instantly — it rises along the curve V(t) = V × (1 − e^(−t/τ)); discharging, it falls along V(t) = V × e^(−t/τ). Both are governed by the time constant τ = R × C, the natural timescale of the RC circuit.

After one time constant the capacitor reaches about 63% of the supply voltage when charging (or falls to 37% when discharging); after 5τ it is within 1% of its final value and is treated as fully charged or discharged. For example, a 1,000 µF capacitor charged through a 1 kΩ resistor has τ = 1,000 × 10⁻⁶ × 1,000 = 1 second, so it is 63% charged after 1 s and essentially full after 5 s. At 5 V that same capacitor stores Q = 0.001 × 5 = 0.005 C and E = ½ × 0.001 × 25 = 0.0125 J.

Enter the supply voltage, capacitance and series resistance and the calculator returns the full charge, the stored energy, the time constant, the settling time (5τ), the voltage at a chosen instant, and the whole charge or discharge curve. These numbers are the everyday basis for RC timing circuits, power-supply smoothing, debounce delays, flash-photography energy storage and the turn-on delays in analogue electronics.

经常问到的问题

RC电路的时间常数是多少?

The time constant τ = R × C is the time to charge to about 63% of the supply voltage. After 5τ the capacitor is regarded as fully charged (>99%).

电容器商店能用多少能量?

E=1⁄2 × C × V2. 5V仓库的1⁄2 × 0.001 × 25 = 0.0125焦耳的1 000微F电容器。

收费和履行之间有什么区别?

向供给的电压上升为V(1 - e( t/ ) e); 排放从启动电压下降为 V( t/ ) 。 两者在5 个时间常数之后都达到~ 99%的变动。

电容器能承受多少电荷?

电荷为Q = C × V, 直径为 Culombs. 5 V. 的A 1,000 微F 电容器持有0.001 × 5 = 0.005 C. 大容量或高压两种电荷都直接储存更多电荷。

电容器完全充电多久?

Practically, after five time constants (5τ = 5RC) it is within about 1% of the supply and treated as full. With a 1 kΩ resistor and 1,000 µF capacitor τ is 1 s, so it is essentially charged after roughly 5 seconds.

每次固定后达到的百分比是多少?

充电量在1 ~ 1%之后达到63%,在2 2%之后达到86%,在3 ~ 2%之后达到95%,在4~ 4%之后达到98%,在5~ 4%之后达到99%。 焦热情况与镜像相同:37%、14%、5%、2%和1%仍停留在同一点。

为什么要加上连环抵抗者?

阻力器设定了充电速度。 没有它, 开关时的当前加压只能受迷路阻力的限制, 并且可能很大; 阻力器可以预测时间, 这正是RC计时器、 过滤器和拆弹电路所依赖的。

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API - 使用代码中的计算器

将此计算器称为自由 JSON 端点 。 不需要按键 。 将字段值发送到下面作为查询参数或 JSON 。 任何您省略的, 都会使用相同的默认值, 此页面预填的默认值是预填的; 未知参数是 400, 而不是静音零 。 读取 API 全部文件 →

终点

GET https://calculator.free/api/v1/capacitor-charge/

curl

curl "https://calculator.free/api/v1/capacitor-charge/?mode=charge&voltage=5&capacitance=1000&resistance=1000"

JavaScript fetch()

const r = await fetch(
  "https://calculator.free/api/v1/capacitor-charge/?" + new URLSearchParams({
    "mode": "charge",
    "voltage": "5",
    "capacitance": "1000",
    "resistance": "1000"
  }));
const data = await r.json();
console.log(data.results);

成果仅是一般指导的估计数,而不是财务、医疗或税务咨询。