Te tātaitai whakaiti voltage

E whakatauria ana te voltage i ngaro i te taha o te aho mai i te roanga, i te auau me te rahi o te kaiārahi.

m
A
mm²
V
Ka kōwhiria he tauine aho hei whakawātea i te rohe i runga ake nei.
%
Ka whakapeka te voltage (V)
Ka whakamutua
Te voltage i te utu (V)
Ka ngaro te hiko (W)
Whakawhanaunga

Ka whakahōutia ngā hua i te wā e tātuhi ana.

Mo tēnei tātaitai

the one-way run, the drop is Vdrop = 2 × ρ × L × I / A, where the factor 2 accounts for the current travelling out to the load and back along the return conductor; a three-phase run uses √3 instead of 2. Here ρ is the resistivity of the metal (copper ≈ 0.0175 Ω·mm²/m, aluminium ≈ 0.0282 Ω·mm²/m), L is the one-way length in metres, I the load current in amps and A

Ko nga pātai e pā ana

He pēhea te tatau i te hinganga o te whakarewa?

Mō te wā kotahi, Vdrop = 2 × ρ × L × I / A. Ko te taumaha 2 e whakahua ana i te rerenga o te auau, i te taha hoki; e toru nga wā e whakamahi ana i te √3 i te wāhi o te 2.

He aha te whakapeka o te whakarewa e whakaaetia ana?

Ko te ture noa iho o te kōaro ko te pupuri i te hinganga katoa i raro i te 3% mō ngā arawhiti ā-rohe me te 5% i te ahuwhānui.

Kopa, arā, he arangi rānei - he mea hira rānei?

Heoi anō, tata tonu ki te 60% te kaha o te ahorangi i te kopera, nō reira he iti iho te pāpāhotanga o te ahorangi o te rahi ōrite.

He aha te taupū e whakamahi ana i te roa o te roanga?

Me rere te au o nāianei ki te utu me te hoki, kia kite ai te arawhiti wā kotahi i te hinganga o ngā kaiārahi e rua — nā reira te āhuatanga o te 2 × roa. Ka whakamahia e ngā arawhiti wā toru te √3 (tata ki te 1.732) i te wāhi, e whakaatu ana i te āhuahanga o te hiko wā toru.

He pēhea te whakaiti i te hinganga o te pūngao?

Ka whakamahia tētahi kaiārahi nui ake (e rua nga wāhanga whakawhiti e tata ana ki te haurua o te hekenga), whakaiti i te nekeneke, te wehenga i te utu i runga i ngā kāwai whakarara, te whakanui rānei i te voltage whakarato. Ko te kopere nui ake te whakatū i te wāhanga i te wāhanga.

He nui te hiko e ngaro ana i roto i te kaitiaki?

Ko te hiko e ngaro ana ko te wā e whakapeka ana te auau, Ploss = Vdrop × I. Ko te 3.5 V e whakapeka ana i te 20 A e whakapeka ana i te 70 W hei wera i roto i te aho — he pūngao e utu ana koe engari kaore e whakamahia, nā reira ko ngā nekehanga roa o te auau e whakamārama ana i te mārō, te kāri iti iho.

Ka taea e au te whakamahi i ngā tauine AWG i te wāhi o te rohe mm²?

Hei. Ko te kōwhiringa o tētahi tauine i roto i te rārangi AWG whakawhanake, ka whakawātea i te āpure āpure me te whakawhitinga o taua tauine i roto i te mm² (hei tauira, 10 AWG ≈ 5.26 mm²), kia taea ai e koe te mahi i roto i te pūnaha tauine e whakamahia ana e ngā kaiwhakakōrero o Amerika ki te Raki.

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API — whakamahi tēnei tātaitai mai i te waehere

E kī ana tēnei tātaitai hei wāhi mutunga kore JSON - kāore he kī e hiahiatia ana. Ka tukuna ngā uara āpure i raro nei hei tohutoro pātai, JSON rānei. Ka pānui te papatono API katoa →

Whakamutunga

GET https://calculator.free/api/v1/voltage-drop/

curl

curl "https://calculator.free/api/v1/voltage-drop/?material=copper&length=50&current=20&area=10&source=230"

JavaScript fetch()

const r = await fetch(
  "https://calculator.free/api/v1/voltage-drop/?" + new URLSearchParams({
    "material": "copper",
    "length": "50",
    "current": "20",
    "area": "10",
    "source": "230"
  }));
const data = await r.json();
console.log(data.results);

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