Àwọn Ìṣàmúlò-ètò

Estimate the voltage lost along a wire run from length, current and conductor size.

Àwọn Ìjánu-ìṣàmúlò-ètò

Ìgbà ìjánu-ìjánu

Àwọn Ìjánu-ìsún

Ààyè Àwọn Àkọ́kọ́

mm²

Àwọn ìṣàmúlò-ètò

Àwọn ìṣàmúlò-ètò ? Yan àwọn ìṣàmúlò-ètò ìṣàmúlò-ètò láti pa ààyè ààyè náà láti inú.

Àwọn Ìṣàmúlò-ètò

Àwọn ìṣàmúlò-ètò àìdá

Ìjádé Voltígì —

_Gba —

Voltage nínú ààyè-iṣẹ́ (V) —

Power lost (W) —

Àwọn Ìṣàmúlò-ètò —

Àwọn Àtòjọ-ẹ̀yàn àwọn ìṣàmúlò-ètò

Àkóónú ìṣàmúlò-ètò yìí

the one-way length of the cable, the area field is the value of the resistivity of the metal (copper ≈ 0.0175 Ω·mm²/m, aluminium ≈ 0.0282 Ω·mm²/m), and the area field is the value of the resistivity of the metal (copper ≈ 0.0175 Ω·mm²/m, aluminium ≈ 0.0282 Ω·mm²/m). The area field is the value of the resistivity of the metal (copper).

Àwọn Àtòjọ-ẹ̀yàn

Bawo ní a ṣe lè ṣé ìṣàmúlò-ètò ìṣàmúlò-ètò?

Fun faaji kan, Vdrop = 2 × ρ × L × I / A. Faaji 2 jẹ fun awọn iroyin ti o wa ni ayika ati pada; faaji mẹta lo √3 ni ibẹrẹ 2.

Ìgbà wo nínú àwọn ààyè-iṣẹ́ náà?

Àwọn àwọn

Copper tabi aluminium — ò jẹ́ àwọn ààyè?

Ya. Aluminum ní àwọn ìṣàfarawé àwọn ìṣàmúlò-ètò tí a fi pamọ́ nínú àwọn à

Kini idi tí ìṣàmúlò-ètò náà fi ló ìgbà mejì nínú ìjánu-ìṣàmúlò-ètò náà?

Ò yẹ kí ìgbàyàn náà lọ́wọ́lọ́wọ́, kí àwọn sáà fáìsì kan-fáìsì lè wó àwọn ààyè tí a fi pamọ́ nínú àwọn conductors náà - bẹ́ẹ̀ nínú àwọn fáìlì 2 × ìgbà. Sáà fáìsì mẹ́tà lo √3 (nípa 1.732) nígbà, tí a fi àwọn àwọn geometry tí a fi pamọ́ nínú agbara fáìsì mẹ́tà.

Bawo ni mo ṣe lè yọ́kúnú ìgbàdá àwọn ìṣàmúlò-ètò tí a fi pamọ́?

Ló aagó nla kan (àwọn ààyè tí a fi pọ̀ jú nínú àwọn ààyè tí a fi pọ̀ jú), fi àwọn ààyè tí a tí n lọ́wọ́lọ́wọ́, fi àwọn ààyè pamọ́ lọ́wọ́lọ́wọ́, tàbí fi àwọn ààyè tí a fi pọ̀ jú pọ̀. Aagó nla kan ní àwọn ààyè tí a fi pamọ́ lórúkọ́ àwọn ààyè.

Ìgbà wo nínú àwọn káàdí ìmúdárà náà?

A 3.5 V drop at 20 A wastes 70 W as heat in the wire — energy you pay for but never use, which is why long high-current runs justify thicker, lower-loss cable.

Ń lè ló àwọn ààyè-iṣẹ́ AWG láti ló àwọn ààyè-iṣẹ́ mm²?

Ya. Yan àwọn ìṣàmúlò-ètò nínú àtòjọ AWG tí a tílàyè náà, ò sí pà ààyè ààyè náà láti inú àwọn ààyè àwọn ìṣàmúlò-ètò tí a lò ní mm² (gẹ́gẹ́ bíi 10 AWG ≈ 5.26 mm²), láti sé lè ṣiṣẹ́ nínú àwọn ìṣàmúlò-ètò àwọn ìṣàmúlò-ètò Ameríka Òkèrẹ́

API — ló àwọn ìṣàmúlò-ètò yìí láti inú ìṣàmúlò-ètò

Fi àwọn ìṣàmúlò-ètò yìí kọ̀ǹpútà yìí láti inú àwọn ààyè-iṣẹ́ JSON tí a tí fi pamọ́ - àwọn bọ́tìnì kò ní àwọn tí a fẹ́. Fi àwọn fálù ààyè-iṣẹ́ sílẹ̀ sí bí àwọn àwọn ìṣàmúlò-ètò àti JSON. Ka àwọn àkọlé API kíkún →

Àwọn Ààyè Ìjánu-ìsún

GET https://calculator.free/api/v1/voltage-drop/

curl

curl "https://calculator.free/api/v1/voltage-drop/?material=copper&length=50&current=20&area=10&source=230"

JavaScript `fetch()`

const r = await fetch(
  "https://calculator.free/api/v1/voltage-drop/?" + new URLSearchParams({
    "material": "copper",
    "length": "50",
    "current": "20",
    "area": "10",
    "source": "230"
  }));
const data = await r.json();
console.log(data.results);

Àwọn àwọn

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