Kātapū pūtaiao

He tātaitai pūtaiao katoa me ngā tāpiri, ngā taupū, ngā hiko, ngā pūtake me ngā tau tōtika - wātea, ā-waiho.

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Mo tēnei tātaitai

s, and it can be used to calculate the radians of a square. The DEG/RAD toggle controls whether angles are read in degrees or radians, so sin(90) gives 1 in degree mode while sin(π/2) gives 1 in radian mode. Constants π, e and τ, factorials, absolute value and both base-10 and natural logarithms are all available. The DEG/RAD toggle controls whether angles are read in degrees or radians, so sin(90) gives 1 in degree mode while sin(π/2) gives 1 in radians mode. For example, sin(45)^2 + cos(45)^2 returns 1, and 5! + sqrt(144) returns 120 + 12 = 120.For example, sin(45)^2 + cos(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1, and sin(45)^2 returns 1

Ko nga pātai e pā ana

He pēhea te whakamahi i a au i ngā waeine i te wāhi o ngā rārangi?

Ka whakamahia te whakarerekētanga DEG/RAD. I roto i te āhuatanga DEG, ka hoatu te hākinakina (90) ki te 1; i roto i te āhuatanga RAD, ka hoatu te hākinakina (π/2) ki te 1. Ka hoatu te āhuatanga ki ngā taumahi tapawhā katoa.

E whai ana rātau i te raupapa o ngā mahi?

He. Ka tātaritia e ia te kīanga katoa, ā, ka hoatu te tōmua paerewa — ngā kōwae, kātahi anō ka whakarea me te wehenga, kātahi anō ka tāpiri me te tangohanga.

He aha nga taumahi e tautokona ana?

E tautoko ana tēnei tātaitai pūtaiao i te hākinakina, te kōaro, te tā, me ō rātou kōaro, te kōaro (take 10), ln, te kōaro2, te sqrt, te cbrt, te exp, te abs, te whakarea, me ngā tautū π, e me τ.

He pēhea te tatau i a au i tētahi taupū, i tētahi pūtake rānei?

Ka whakamahia ^ mō ngā hiko, nō reira ko te 2^10 te 1024, ā, ko sqrt (), cbrt rānei () mō ngā pūtake tapawhā me ngā pūtake kupiki. Ka mahi hoki tētahi hiko hautanga — 27^ (1/3) e hoatu ana ki te 3 — nā te mea ka tātaritia te kīanga katoa me te tōmua tika.

He aha te rerekētanga i waenganui i te taupū kōaro me te ln?

Ko te taupū kōaro te taupū kōaro pūtake-10, nō reira ko te taupū kōaro (1000) he 3, i te wā ko te taupū kōaro māori o ln ki te pūtake e, nō reira ko ln(e) he 1. Tērā anō hoki te taupū kōaro mō te pūtake-2 taupū kōaro.

He pēhea te tatau i tētahi taupū whakarea?

Ka tāuru i tētahi tau tōpū i muri i te taumahi āhuatanga, hei tauira, 5! e tuku ana i te 120 (5 × 4 × 3 × 2 × 1). He tere te tupu o ngā āhuatanga, nō reira ka puta mai ngā tāurunga nui ki ngā hua tino nui.

Ka taea e au te whakamahi π me te e i roto i tētahi kīanga?

He. Tirohia hāngai tonu te π (pi) me te e ki roto i tētahi kīanga, pēnei i te 2*π*5 mō tētahi porohita, e^2 rānei, ā, ka whakakapia ki to rātau tika katoa i mua i te arotakenga o te kīanga.

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